A model rocket launched directly upward at a speed of 16 meters per second from a helght of 2 meters . The f(t) = - 4.9t ^ 2 + 16t + 2 models the relationship between the height of the rocket and the time after launch, t. In seconds. Which is the maximum height meters the rocket will reach Round to two decimal places Provide your answer below: meters

f(t) = 15.06 m

Step-by-step explanation:

The relationship between the height of the rocket and the time after launch, t. In seconds is given by :

We need to find the maximum height the rocket will reach the ground.

When it reaches the ground,

f(t) = 0

So,

Maximum height,

f'(t) = 0

Put t = 1.63 in equation (1).

So, the maximum height of the rocket is 15.06 m.

yes

step-by-step explanation:

the 8 in 8,420 is in the thousands place so it's value is 8 thousand.

the 8 in 6,870 is in the hundreds place so it's value is 8 hundred.

divide 8000 by 800 to find the answer:

8000 / 800 = 10

the 8 in 8,420 is 10 times greater than the 8 in 6,870