Let f(x) be continuous on [0,∞) and twice differentiable on (0,∞). If f(0)=0 and f′′(x)>0 on (0,∞) prove that for all x>0, f(x)

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

- both graphs increase on their domain.

- the graphs of both functions have the same x-intercept.

- neither graph has a y-intercept.