Mathematics, 08.03.2021 19:40, jgnjanjdknsjrr9358

In 2009 a survey of Internet usage found that 79 percent of adults age 18 years and older in the United States use the Internet. A broadband company believes that the percent is greater now than it was in 2009 and will conduct a survey. The company plans to construct a 98 percent confidence interval to estimate the current percent and wants the margin of error to be no more than 2.5 percentage points. Assuming that at least 79 percent of adults use the Internet, which of the following should be used to find the sample size (n) needed? a. 1.96 â0.5/n = 0.025
b. 1.96 â0.5(0.5)/n = 0.25
c. 2.33 â0.5(0.5)/n =0.05
d. 2.33 â0.79(0.21)/n= 0.025

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In 2009 a survey of Internet usage found that 79 percent of adults age 18 years and older in the Uni...