A particle moves along the y-axis so that its position at time t is given by y(t)=t^2 tan(1/t) for t>1. Show that the velocity of the particle at time t is given by v(t)=2t tan(1/t) - sec^2 (1/t) for t>1.​

given : the shape of his satellite can be modeled by   where x and y are modeled in inches.

now,the given equation   is a equation of parabola.

here, coefficient of x is positive, hence the parabola opens rightwards.

on comparing this equation with standard equation , we get

in standard equation, coordinates of focus=(0,m)

thus for given equation coordinates of focus=(0,1.5)

step-by-step explanation:

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )

14 x 10 5

step-by-step explanation:

10 5 = 100,000

14x10,000 = 140,000