Find the angle between the vectors to the nearest tenth of a degree 4+ 3 & 3+ 5
a) 12.20
b) 18.20
c) 22.20
d) 25.20

the zero at the end of the answers is a degree sign

we need more info to solve this

ratio is 2 : 9

the answer is three

13.5 : 3

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )

the correct answer would be the third option