A triangle has a perimeter of 40cm. If the three sides of the triangle are n, 3n−5, and 3n−4, what is the length of each side?

9514 1404 393

  7, 16, 17

Step-by-step explanation:

The sum of the lengths of the three sides is the perimeter:

  (n) +(3n -5) +(3n -4) = 40

  7n -9 = 40 . . . . . . . . . . . . . . collect terms

  7n = 49 . . . . . . . . . . . add 9

  n = 7 . . . . . . . . . divide by 7

Then the side lengths are ...

  n = 7

  3n -5 = 16

  3n -4 = 17

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: