Divide 4897 by 6 step by step ​

0816.166 recurring.

Step-by-step explanation:

6 times table : 6, 12, 18, 24, 30, 36, 42, 48.

6 ÷ 4= 0 so 6 didnt go into 4 leaving it to be a remainder so you carry the number over.

how many times does 6 go into 48, which is 8 times.

so far, this is what it would look like.

6 goes into 9, 1 leaving a remainder of 3,so we carry it over to the next number.

how many times does 6 goes into 37, which is 6 times leaving a remainder of 1.

Now we need to go into the decimals because we still have a remainder.

so we now have 10, 6 goes into 10, 1 remainder 4.

how many times 6 goes into 40, 6, remainder 2.

6 goes into 20, 3 times remainder 4. this is going to end up recurring because we ended up with the same number so your full answer, putting all the numbers together would be

0816.166 recurring.

step-by-step explanation:

the first 5 right here the next 5 i will upload as separate question

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!