A bus as speed of 20m/s begin to slow at constant acceleration of 8.00m/s2 along a straight line find the average speed for the 5al. s interv

-20 m/s.

Step-by-step explanation:

The computation of the average speed is shown below:

Given that

The initial velocity of the bus, u = 20 m/s

Aceleration of the bus, -a = 8 m/s²

time of motion, t = 5 s

Now The final velocity of the bus is  

v = u + at

v = 20 + (-8 × 5)

v = 20 - 40

v = -20 m/s.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

the formula of a slope:

we have the points (-2, 7) and (2, 3). substitute: