PLEASE HELP ME! 1.)Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not have a solution.

2.)Create a single variable linear equation that has one solution. Solve the equation algebraically to prove that there is one distinct solution for the equation.

3.)Create a single variable linear equation that has infinitely many solutions. Solve the equation algebraically to prove that there is an infinite number of solutions for the equation

A linear equation can have no, one or infinite solutions.

Step-by-step explanation:

No Solution:

Consider the equation 8x - 19 = 8x + 19

Subtract 8x from both the sides. We get:

8x - 8x - 19 = 8x - 8x + 19

⇒ - 19 = 19

This is absurd. So, this system of equations has no solution.

One Solution:

For the equation 9x + 5 = 14

⇒ 9x = 9

⇒ x = 1 the only solution to the equation.

Infinite Solutions:

The solution to the equation 3x = 3x are infinite.

Whatever the value of x the equation always remains the same. So, we have infinite values of x that can satisfy the equation

Step-by-step explanation:

have a great day

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b