2 The length of this rectangle is x cm. a The width of the rectangle is 2 cm less than the length.
Write down an expression for the width of the rectangle, in centimetres.
b The perimeter of the rectangle is 84 cm. Write down an equation to show this.
c Solve the equation.
d Find the area of the rectangle.

a. The width of the rectangle is x-2cm

b. length is 21.5 cm and breadth is 19.5cm

c. area is 419.25 cm sq.

Step-by-step explanation:

Let the length be x and the breadth be x-2

perimeter = 84 = 2(l+b) = 2×(x+x-2)

2×(2x-2)=84

4x-2 = 84

4x = 86

x= 86/4

x= 21.5

length is 21.5 and breadth is 21.5-2 = 19.5

area = l×b

= 21.5 ×19.5

= 419.25cmsq.

hope it helps

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation:

the answer is simply just 6n add the two together as they have an n