The verticals of the triangle shape are A (-2, 4) , B (-2,3) , and C (-5,2). If ABC is reflected across the line y = -1 to produce the image of A'B'C', What's the coordinate of B' after a reflection across the line y=-1? ​

Given:

The vertices of a triangle are A (-2, 4) , B (-2,3) , and C (-5,2).

Triangle ABC is reflected across the line y = -1 to produce the image of A'B'C'.

To find:

The coordinate of B' after a reflection across the line y=-1.

Solution:

If a figure is reflected across the line y=b, then

The given triangle ABC is reflected across the line y=-1. So, the rule of reflection is

The coordinates of point B are (-2,3). So,

Therefore, the coordinates of point B' are (-2,-5).

i hope this is what you were looking for.

see attached graph

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y