Mathematics, 06.03.2021 09:00, raishagibson
Vector curve problem. Part of a cross-country skier's path can be described with the vector function r = <2 + 6t 2 + cos(t), (15 − t)(1 − sin(t))> for 0 ≤ t ≤ 15 minutes, with x and y measured in meters.
The derivatives of these functions are given by x′(t) = 6 − 2sin(t) and y′(t) = −15cos(t) + tcos(t) − 1 + sin(t).
Find the acceleration vector of the skier when the skier's horizontal position is x = 60.
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Vector curve problem. Part of a cross-country skier's path can be described with the vector function...
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