A classroom is arranged with 6 seats in the front row, 8 seats in the middle row, and 10 seats in the back row. The teacher randomly assigns seats to students as they enter the classroom. What is the probability that the first student who enters the classroom will be assigned a seat in the front row?

Step-by-step explanation:

First add them all up to get the total amount of seats.

6+10+8=24

there are 6 seats in the front row. so that means it will be

24÷6=0.25

0.25×100=25%

Probability can be answered with a fraction, decimal or a percentage, they are all correct.

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: