Mathematics, 05.03.2021 22:50, edginutystudent
The figure below shows a square ABCD and an equilateral triangle DPC: ABCD is a square. P is a point inside the square. Straight lines join points A and P, B and P, D and P, and C and P. Triangle D Ted makes the chart shown below to prove that triangle APD is congruent to triangle BPC: Statements Justifications In triangles APD and BPC; DP = PC Sides of equilateral triangle DPC are equal In triangles APD and BPC; AD = BC Sides of square ABCD are equal In triangles APD and BPC; angle ADP = angle BCP Angle ADC = angle BCD = 90° so angle ADP = angle BCP = 60° Triangles APD and BPC are congruent SAS postulate What is the error in Ted's proof?
Answers: 3
Mathematics, 21.06.2019 17:20, ponylover9655
Read the situations in the table below. then drag a graph and equation to represent each situation. indicate whether each of the relationships is proportional or non-proportional. edit : i got the right answer its attached
Answers: 2
Mathematics, 21.06.2019 17:50, tiffcarina69
F(x) = x2 − 9, and g(x) = x − 3 f(x) = x2 − 4x + 3, and g(x) = x − 3 f(x) = x2 + 4x − 5, and g(x) = x − 1 f(x) = x2 − 16, and g(x) = x − 4 h(x) = x + 5 arrowright h(x) = x + 3 arrowright h(x) = x + 4 arrowright h(x) = x − 1 arrowright
Answers: 2
The figure below shows a square ABCD and an equilateral triangle DPC: ABCD is a square. P is a point...
Mathematics, 11.01.2021 23:00
Mathematics, 11.01.2021 23:00
Mathematics, 11.01.2021 23:00
Mathematics, 11.01.2021 23:00
Mathematics, 11.01.2021 23:00
Mathematics, 11.01.2021 23:00
Mathematics, 11.01.2021 23:00