The perimeter of a rectangle is 70in the length of the rectangle is 5 less than 3 times its width what is the width of the rectangle

width is 10in and the length is 25

Step-by-step explanation:

perimenter is 70in

divide 79 by 2 which equals 35

you subtract 5 because the length is five less

you divide 30 by 3, you get 10, that's the width and you subtract 5 from 30 to get the length which is 25, you can check your answer by adding the newfound length and width and you should get half of the perimeter given at the beginning of the question

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation: