A fireworks rocket is launched from a hill above a lake. The rocket will fall into the lake after exploding at its maximum height. The rocket's height above the surface of the lake is given by g(x)=
-16x² + 64x + 80. What is the maximum height of the rocket?

(2,114)

Step-by-step explanation:

g(x)= -16x² + 64x + 80

Plug 2 in to check if it's correct.

g(2)= -16(2)² + 64(2) + 80

-16(4)+128+80

-64+128+80

= 144

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

step-by-step explanation:

3024 rhe base is what up in worry about