Show your work, this is a homework and I am force to show work. A line passes through the points (-1/2,1) and has a slope of 2.

Write in slope intercept-form, how do you know.

The line also passes through the point (-8,k). Find the value of K

x2, y2)

To find slope, m, given two points, (-1, 2) and (3, 4)

m = (y2 - y1)/(x2 - x1)

Once you have the slope (did you get 1/2?), you're ready to find the y-intercept. Use the slope-intercept equation of a line and either point.  I'd choose point #2 since they are positive numbers, but it doesn't matter which point you use.

y = mx + b  <-- use x2 = 4 and y2 = 3

3 = 1/2(4) + b  <-- solve for b

3 = 2 + b

1 = b

Rewrite the slope-intercept equation of a line replacing m = 1/2 and b = 1.

y = mx + b

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

b.my answer is b.

brainliest