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Proving the Parallelogram Side Theorem
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Given: ABCD is a parallelogram,
Prove: ABCD and BC-DA
Angles Segments Triangles Statements Reasons
ZBAC
ZBCA
ZDAC
ZDCA
B
С
Statements
1. ABCD is a parallelogram
2. AB || CD
3. BC || DA
4. draw AC
Reasons
1. given
2. def. of parallelogram
3. def. of parallelogram
4. unique line postulate
D
alternate interior angles theorem
Think about the angles created by AC.

im confused what the question is

Step-by-step explanation:

Sorry usually I would give a proper answer but the question doesn't make since

Step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3