To prepare for virtual learning the school is purchasing extra keyboards, mice, and PC cameras. They have a budget of $1500 to spend on $30 keyboards, $20 mice, and $50 cameras. Additionally, the number of mice should be equal to that of keyboards and twice the number of cameras. How many of each item should he buy? explain please​

20 keyboards and mice, 10 cameras.

Step-by-step explanation: They need the same number of keyboard and mice, and they want to get half the amount of cameras they do keyboard and mice. They have a budget of $1500 so 20 keyboards and mice as well as 10 cameras is the most optimal purchase.

30*20=600

20*20=400

50*10=500

600+400+500=1500

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐