Riya is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 25 m, 12 m and 8 m respectively. From each can of
paint 200 m2 of area is painted. How many cans of paint will she need to
paint the room?

6

Step-by-step explanation:

We firat gotta calculate the surface area of the walls and the ceiling

Walls

(25 × 8) m2 × 2

=200m2 × 2

=400m2

(25 × 12)m2 × 2

=300m2 × 2

=600m2

We have to times it by 2 because there is 2 walls

Ceiling

(12 × 8) m2

=96m2

Total

400m2 + 600m2 + 96m2

=1096m2

Cans needed

1096m2 ÷ 200m2 = 5 remainder of 96

Remainder becomes another can so

5 + 1 = 6

LSA of a cuboid = 2(l+b) h

= 2×( 25+12) 8

= 592m square

how many cans reqired?

1 can = 200 m sq

therefore, 592 msq = 592÷200

= 2.96

7

step-by-step explanation:

the answer would be 7

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )