Mathematics, 05.03.2021 01:50, raymond5799

X, Y and Z are three mutually exclusive events. P(X) = 0.4, P(Y) = 0.3 and P(
XU Z) = 0.6.
Find:
() P(XUY)
(i) P(Z)
(ii) The probability that none of X, Y or Z
happens

Answers: 2

Show answers

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X, Y and Z are three mutually exclusive events. P(X) = 0.4, P(Y) = 0.3 and P(
XU Z) = 0.6.

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X, Y and Z are three mutually exclusive events. P(X) = 0.4, P(Y) = 0.3 and P( XU Z) = 0.6. Find: () P(XUY) (i) P(Z) (ii) The probability that none of X, Y or Z happens

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Other questions on the subject: Mathematics

Questions in other subjects:

X, Y and Z are three mutually exclusive events. P(X) = 0.4, P(Y) = 0.3 and P(
XU Z) = 0.6.
Find:
() P(XUY)
(i) P(Z)
(ii) The probability that none of X, Y or Z
happens