Write the equation of the line through (6, -3) with a slope of 2/3

m = rise/run= y₂ - y₁ x₂ - x₁

m =slope

(x₁, y₁) = coordinates of first point in the line

(x₂, y₂) = coordinates of second point in the line

From the web

What About y = mx + b ? You may already be familiar with the "y=mx+b" form (called the slope-intercept form of the equation of a line). It is the same equation, in a different form! The "b" value (called the y-intercept) is where the line crosses the y-axis.

Um- I've never done this before- so- like that? qwq"""

kk.bj.

step-by-step explanation:

.mnm.kn.kj

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )