The sum of the ages of Gusion and Lesley is 42. Four years ago, Gusion was twice as old as Lesley. Find the present age of each.

Gusion = 2years

Lesley= 40years

Step-by-step explanation:

Let Guison age be x

Let Lesley age be y

If the sum of the ages of Gusion and Lesley is 42, then;

x+ y =42 ... 1

Four years ago

Guison age = x - 4

Lesley age = y - 4

If four years ago, Gusion was twice as old as Lesley, then;

x - 4 = 2(y-4)

x - 4 = 2y - 9

x - 2y = -9+4

x - 2y = -5 2

Substract 1 from 2;

y + 2y = 1+5

3y = 6

y = 2

From 1;

x = 42 - y

x = 42-2

x = 40

Hence present age pf Guison is 2 years

Present age of Lesley is 40 years

answer: he is 272195

step-by-step explanation: all you have to do is multiple 3535 and 77 and it equals 272195

12

step-by-step explanation:

12 + 5 = 17

12x2=24

24-7=17