A parallelogram has vertices (5,0), (3, -3), (-4, -3) and (-2, 0) The diagonals of the parallelogram intersect at their midpoints. A. What are the coordinates of the
intersection of their diagonals? Justify the answer algebraically.

(0.5 , -1.5)

Step-by-step explanation:

intersection of their diagonals (E): right at the mid-point of segment AC or BD

A (5 , 0)  and C (-4 , -3): E (x , y)

x = (5 + -4 ) / 2 = 0.5

y = (0 + -3 ) / 2 = - 1.5

E ( 0.5 , - 1.5)

check with BD: x = (3 + -2) / 2 = 0.5        y = (-3 + 0) / 2 = - 1.5

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step-by-step explanation:

answer: c

(2, -4)

goes 7 to the

(9, 4)

easy