You can model an arch at your school using the equation y = -0.7(x - 3.5) (x +3.5), where x and y are measured in feet. The x-axis represents the ground, Find the width of the arch at ground level

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

12

step-by-step explanation:

i think the answer is 90 hope this

150

step-by-step explanation:

(sorry i'm not typing it again just read the other two explanation sections i just typed it'll be the same.)