A rectangular piece of card has a perimeter of 40cm and width of 8cm. the area of the card is

Area of the rectangular piece of card = 96 sq.cm

Step-by-step explanation:

here we go,

peremeter ( p ) = 2 × ( length (L) + width (B) )

so,

=》40 = 2 ( L + 8 )

=》40 / 2 = L + 8

=》20 = L + 8

=》L = 20 - 8

=》L = 12

so, length of the card = 12cm

now,

Area (A) = length (L) × width (B)

=》A = 12 × 8

=》Area = 96 sq.cm

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

explanation:

step-by-step explanation: