Ben rolled a number cube numbered one through six. It landed on an odd number 30 times. What is the probability that it lands on an odd number on the next roll?

1 /2

Step-by-step explanation:

Sample space of number cube : (1, 2, 3, 4, 5, 6)

Odd numbers on cube : (1, 3, 5) = 3 odd numbers

Since each roll of number cube is independent, the number of times it has landed between fire does not matter :

Therefore, probability of landing on a odd number is :

P = required outcome / Total possible outcomes

P = 3 / 6

P = 1/2

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the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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