Let ∠1, ∠2, ∠3, and ∠4 have the following relationships. ∠1 and ∠2 are vertical angles.
∠3 and ∠4 are right vertical angles.
∠3 is adjacent to both ∠1 and ∠2.
What is the sum of the measure of ∠4 and the measure of ∠1 minus the measure of ∠2?

i swear im abt to go crazy- math sucks :)

90°

Step-by-step explanation:

Ok, I get it now.

Draw two perpendicular lines. Starting at any of the right angles, name them 1, 3, 2, 4 going around in order.

Now you have vertical angles 1 and 2, vertical angles 3 and 4, and angle 3 is adjacent to angles 1 and 2. this is exactly what the description states.

Since angles 3 and 4 are right angles, then all angles are right angles.

m<1 = m<2 = m<3 = m<4 = 90

m<4 + m<1 - m<2 = 90 + 90 - 90 = 90

90°

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b