PART A: APPLICATION (10 marks) 1. Tom weighs six kilograms less than twice Jerry's weight. If the sum of their weights is 102
kilograms, how much does each person weigh? You can choose to solve by substitution or
elimination for this question. Show your work for full marks.
(5 marks)
Let T

Jerry's weight is 36kg and tom's weight is 66kg

Step-by-step explanation:

According to the given condition:

Let,tom's weight =x

Jerry's weight=y

So,

X=2y-6 ---(1)

X+y=102(2)

Put value of x from eq 1 in 2

2y-6+y=102

3y-6=102

3y=102+6

3y=108

Y=108/3=36

Jerry's weight is 36.

Put value of y in eq 1

X= 2(36) -6

X=72-6

X=66

So, Tom's weight is 66kg

-1/2 +2

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?