Mathematics, 03.03.2021 20:40, sovprints

The first one is done and the options for number four are: w(2w+12)=160
2w^2+12w-260=0
2w^2+12w=260
w^2+6w-130=0

The first one is done and the options for number four are:

w(2w+12)=160
2w^2+12w-260=0
2w^2+12w=2

Answers: 3

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The first one is done and the options for number four are: w(2w+12)=160
2w^2+12w-260=0
...