Answer: the correct answer is 10step-by-step explanation: let the number be n, then the expression becomes,then“twelve more than the quotient of a number and two, decreased by four” is
![(\frac{n}{2}+12)-4](/tex.php?f=(\frac{n}{2}+12)-4)
when n=4,we substitute 4 whetever we see n to get,
![(\frac{4}{2}+12)-4](/tex.php?f=(\frac{4}{2}+12)-4)
we simplify to obtain,
![=(2+12)-4](/tex.php?f==(2+12)-4)
we further simplify to get,
![=14-4=10](/tex.php?f==14-4=10)
therefore the correct answer is c.