The following distribution is not a probability distribution because x
-5
-4
-3
-2
P(x) 0.08 0.23 0.44 0.12 0.24
A) The values of x are negative
B) The probability values are not increasing
C The probability values do not add to 1
D) The probability values are not discrete

C The probability values do not add to 1

Step-by-step explanation:

Given

The above table

Required

Why is it not a probability distribution

In probability, the sum of all probabilities must equal 0.

But in this case:

Because:

Hence:

Option (c) answers this question

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12