The sad state lottery requires you to select a sequence of four different numbers from 0 through 47. (Order is important.) You are a winner if your sequence agrees with that in the drawing, and you are a fool prize winner if your selection of numbers is correct, but in the wrong order. What is the probability of being a winner? (Enter your probabilities as fractions.) What is the probability of being a fool prize winner? What is the probability that you are either a winner or a fool prize winner?​

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1

i dont know sorry

step-by-step explanation:

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.