three odd consecutive integers are such that 3 times the smallest is 9 more than twice the largest .find the three numbers​

17, 19, 21

Step-by-step explanation:

Three consecutive odd numbers: x, x+2, x+4 (since odd numbers occur every other number)

Just to show you that the numbers are x, x+2, and x+4, just say x is 13 then x+2 is 15 and x+4 is 17 (3 consecutive odd numbers)

Now the second equation:

3x = 2(x+4) + 9

three times smallest number (which is x) is equal to 2 times the largest number (x+4) plus 9

Now solve

3x = 2(x+4) +9

3x = 2x + 8 + 9

3x = 2x + 17

x = 17

x+2 = 19

x+3 = 21

i got 142 as my answer

step-by-step explanation: