Y=3/2x-9
I need to find the x-intercept and the y-intercept with work plsss

Hi there!

x-int: (6, 0)

y-int: (0, -9)

y = 3/2x - 9

Begin by finding the x-intercept. The x-intercept is located where y = 0, therefore:

0 = 3/2x - 9

Isolate for x by adding 9 to both sides:

9 = 3/2x

Divide both sides by 3/2x:

9 * 2/3 = x

x = 6. Thus, the x-intercept is at (6, 0).

Find the y-intercept by finding the y-value at which x = 0:

y = 3/2(0) - 9

y = -9. The y-intercept is at (0, -9).

(5x-1)^2= (5x)^2-2(5x)×1+(1)^2=25x^2-10x+1