Find the equation of the line that goes through the point ( 6, 5) and has a slope of 1/3

Answer (assuming it can be slope-intercept form):

Step-by-step explanation:

Since we already know a point the line intersects and its slope, we can use the point-slope formula to write an equation, then convert it to slope-intercept form.

Substitute values for , , and . Since represents the slope, substitute in its place. Since and represent the x and y values of one point the line intersects, use the x and y values of (6,5) and substitute them into the equation. Substitute 6 for and 5 for . Then, isolate y to put it into slope-intercept form and find an

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

answer: 7. if the functions had a negative leading coefficient and is of even degree, which statement about the graph is true?

step-by-step explanation: