The means and mean absolute deviations of the individual times of members of two relay swim teams are shown in the table below. Means and Mean Absolute Deviations of
Individual Times of Members of 4 times 200 meter Relay Swim Teams

Team A
Team B
Mean
127.9 s
127.4 s
Mean Absolute Deviation

0.26 s

0.23 s
The difference of the means is found and then compared to each of the mean absolute deviations. Which is true?
The difference between the mean times is about equal to the mean absolute deviation of the data sets.
The difference between the mean times is about 2 times the mean absolute deviation of the data sets.
The difference between the mean times is about 5 times the mean absolute deviation of the data sets.
The difference between the mean times is about 16 times the mean absolute deviation of the data sets.

team b should be the answer

it's team B

Step-by-step explanation:

i took the test:)

goodluck

step-by-step explanation:

the degrees would remain the same ( the number to the left of the decimal point.

the multiply the decimal by 60 to get the minutes and use the numbers to the left of the decimal point.

then multiply the decimal portion of that by 60 for the seconds and round off as needed.

39 .956652

the 39 remains the degrees.

the minutes = 0.956652 x 60 = 57.39912

the minutes = 57

the seconds = 0.39912 x 60 = 23.95 = 24 ( rounded to nearest tenth)

so 39.956652 = 39 degrees, 57 minutes and 24 seconds

-75.159809

the -75 remains the degrees

the minutes = 0.159809 x 60 = 9.58854

the minutes = 9

the seconds = 0.58854 x 60 = 35.31, rounded to nearest tenth = 35.3 seconds

so -75.159809 = -75 degrees, 9 minutes and 35.3 seconds.

the first coordinate is north or south, since it it positive it is north.

the second number is east or west, because it is negative it is west.

39 degrees, 57 minutes and 24 seconds n

-75 degrees, 9 minutes and 35.3 seconds w