In ΔEFG, the measure of ∠G=90°, FG = 4.8 feet, and GE = 3.5 feet. Find the measure of ∠F to the nearest degree.

34

Step-by-step explanation:

I used GeoGebra (that's what I use for graphing in my Geography class)

36

Step-by-step explanation:

What function uses the ADJACENT and the OPPOSITE?

\text{SOH-CAH-TOA}

SOH-CAH-TOA

\tan F = \frac{\text{opposite}}{\text{adjacent}}=\frac{3.5}{4.8}

tanF=

adjacent

opposite

​

=

4.8

3.5

​

\tan F = \frac{3.5}{4.8}

tanF=

4.8

3.5

​

F=\tan^{-1}(\frac{3.5}{4.8})

F=tan

−1

(

4.8

3.5

​

)

F=36.098\approx 36^{\circ}

F=36.098≈36

∘

36

Step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.