The high temperature this Sunday is expected to be 5 degrees warmer than the high temperature this Saturday. Using the line c=2t-89c=2t−89, how many more cups of lemonade should Lin expect to sell on Sunday than Saturday? Explain or show your reasoning.

Lin should expect to sell 10 cups more

Step-by-step explanation:

The line c = 2t − 89 relates the cups Lin expect to sale (c) with the high temperature of the day (t)

If high temperature on Saturday is t1, then high temperature on Sunday is (t1+5)

Cups sold on Saturday are: 2t1 − 89

Cups sold on Sunday are:  2(t1+5) − 89 = 2t1 + 10 - 89

Cups sold on Sunday - Cups sold on Saturday:

2t1 + 10 - 89 - (2t1 − 89) = 2t1 + 10 - 89 - 2t1 + 89 = 10

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;