Step 2: Construct regular polygons inscribed in a circle. a) Construct an equilateral triangle inscribed in a circle using the construction tool. Insert a
screenshot of the construction here. Alternatively, construct an equilateral triangle inscribed in a
circle by hand using a compass and straightedge. Leave all circle and arc markings. (10 points)
b) Construct a regular hexagon inscribed in a circle using the construction tool. Insert a screenshot
of the construction here. Alternatively, construct a regular hexagon inscribed in a circle by hand
using a compass and straightedge. Leave all circle and arc markings. (10 points)
c) Construct a square inscribed in a circle using the construction tool. Insert a screenshot of the
construction here. Alternatively, construct a square inscribed in a circle by hand using a compass
and straightedge. Leave all circle and arc markings. (10 points)

answer: 8

step-by-step explanation:

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.

add them

step-by-step explanation:

idk you did not give the options or numbers so you cant solve it