What is the domain of the relation? On a coordinate plane, a graph of an image has 3 connected lines. The first line goes from (negative 4, negative 4) to (negative 2, 1). The second line goes from (negative 2, 1) to (1, 1). The third line goes from (1, 1) to (6, 4). There are closed circles at (negative 4, negative 4) and (6, 4).

Evaluate 8x2 + 9x − 1 2x3 + 3x2 − 2x dx. solution since the degree of the numerator is less than the degree of the denominator, we don't need to divide. we factor the denominator as 2x3 + 3x2 − 2x = x(2x2 + 3x − 2) = x(2x − 1)(x + 2). since the denominator has three distinct linear factors, the partial fraction decomposition of the integrand has the form† 8x2 + 9x − 1 x(2x − 1)(x + 2) = correct: your answer is correct. to determine the values of a, b, and c, we multiply both sides of this equation by the product of the denominators, x(2x − 1)(x + 2), obtaining 8x2 + 9x − 1 = a correct: your answer is correct. (x + 2) + bx(x + 2) + cx(2x − 1).