Solve the following pairs of simultaneous equations by method of substitution. 1. x − y = 1
x + y = 3
2. y − x = 1
x + y = 5
3. y = 4x + 4
x + y = 14
4. a = 4 − b
2a + b = 1
5. 5x − 2b = 1
x = 5 − 2b
6. x − y = 4
x + 2y = 10
7. a − 2b = 1
3a − 4b = 1
8. 4x − 3y = 1
x − 2y = 4
9. a + 2p = 4
x − 2y = 6
10. 2x + 3y = 5
−x + 2y = 8
11. y − x = 2
2y − 4x = 10
12. x + 6y = 22
2x + 10y = 38
13. 2x − y = 5
x + y = 4
14. x + y = 7
2x + y = 10
15. x + y = 144
2x − 3y = 63

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

answer: h

step-by-step explanation:

the one that has a slope of 1/2 and is positive.

step-by-step explanation: 2 buckets 1 trip ; 4 buckets 2 trips and so on.