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The perimeter of a rectangular garden is 68 yards. The width of the garden is five yards less than twice the length.
(a) Find the length and width of the garden.
(b) What is the area of the garden?
The length of the garden is
(Type an integer or a decimal.)
The width of the garden is
V (Type an integer or a decimal.)
The area of the garden is
(Type an integer or a decimal.)

a. Length = 13 yards and Width = 21 yards.

b. Area of rectangle = 273 square yards.

Step-by-step explanation:

Let the length of the rectangular garden be L

Let the width of the rectangular garden be W

Given the following data;

Perimeter of garden = 68 yards

Translating the word problem into an algebraic equation, we have;

W = 2L - 5 ......equation 1

Note: The formula for calculating the perimeter of a rectangle is;

68 = 2L + 2W ........equation 2

Substituting eqn 1 into eqn 2;

68 = 2L + 2(2L - 5)

68 = 2L + 4L - 10

68 = 6L - 10

6L = 68 + 10

6L = 78

L = 78/6

L = 13 yards

To find the width;

W = 2L - 5

W = 2(13) - 5

W = 26 - 5

W = 21 yards.

b. To find the area of the garden;

Area of rectangle = length * width

Area of rectangle = 13 * 21

Area of rectangle = 273 square yards.

step-by-step explanation:

it will be a cylinder. with a diameter of 8 and 4 single pieces high

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation: