The radius of a cylindrical garden roller is 70 cm and its length is 2 m. How much area will it cover in 5 revolutions?

439822.95 cm²

Step-by-step explanation:

The radius of a cylindrical garden roller is 70 cm and its length is 2 m. How much area will it cover in 5 revolutions?

The formula to solve the above question is given as:

Area covered = Curved surface area × Number of revolutions

Step 1

We find the curved surface area of the cylindrical garden

Area = 2πrh

r = 70cm

h = 2m

Convert height to cm

1m = 100cm

2m = x

Cross Multiply

x = 2 × 100 cm = 200cm

Hence,

Area = 2 × π × 70 × 200

= 87964.59cm²

Step 2

Area covered = Curved surface area × Number of revolutions

= 87964.59cm² × 5 revolutions

= 439822.95 cm²

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

the answer is c.

step-by-step explanation: