Consider the following function and closed interval.
y = 3x^2/3 − 2x, [−1, 1]
...
Mathematics, 28.02.2021 19:50, diamondscott9297
Consider the following function and closed interval.
y = 3x^2/3 − 2x, [−1, 1]
![Consider the following function and closed interval.
y = 3x^2/3 − 2x, [−1, 1]](/tpl/images/2185/3683/7edc1.jpg)
Answers: 3
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