According to the National Office of Vital Statistics of the U. S Department of Health and Human Services, the average number of accidental drownings per year in the United States is 3.0 per 100,000 population. Find the probability that in a city of population 200,000 there will be (a) 0.
(b) 2.
(c) 6.
(d) 8.
(e) between 4 and 8.
(f) fewer than 3, accidental drownings per year.

National Office of Vital Statistics of the U.S Department of Health and Human Services

The probability that in a city of population 200,000 there will be:

(c) 6.

Step-by-step explanation:

a) Data and Calculations:

Average number of accidental drownings per year in the United States = 3.0 per 100,000 population

Therefore, the accidental drownings per year when the population increases to 200,000 will be 3.0/100,000 * 200,000 = 6

b) In the population of 100,000, the average number of accidental drownings per year is estimated to be equal to 3.0.  When the population increases to 200,000, the average accidental drownings per year will double because the population also doubled from 100,000 to 200,000.

3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3

x = 3 ± √(5+y)