a bag contains 4 blue and 6 green marbles. two marbles are selected at a random from the bag. if the first marble is not replaced before the second marble is drawn

4 ÷ 10

Step-by-step explanation:

The computation of P is shown below:

If we add two marbles i.e.

= 4 + 6

= 10 marbles

Now if we draw the second marble

P(blue) = Blue marbles ÷ total marbles

= 4 ÷ 10

In the other case

P( blue second given a green first) = 4 ÷ 10

no, because the sides are not congruent

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.