6th grade math problem due in 4 hours I have been trying this problem for 32 min and still can't figure it out someone plz help Circle A has a diameter of 8 inches, a circumference of 25.12 inches, and an area of 50.24 square inches. The diameter of circle B is 3 inches, the circumference is 9.42 inches, and the area is 7.065 square inches.

Part A: Using the formula for circumference, solve for the value of pi for each circle. (4 points)

Part B: Use the formula for area and solve for the value of pi for each circle. (4 points)

Part C: What observation can you make about the value of pi for circles A and B? (2 points)

Step-by-step explanation:

C =2pi*(d/2) A = pi (d/2)^2

Part A

A B

25.12 = 2pi *(8/2) 9.42 = 2pi (3/2)

25.12 = 8pi 9.42 = 3pi

pi = 25.12 / 8 pi = 9.42 / 3

pi ≈ 3.14 pi = 3.14

Part B

A B

50.24 = pi (8/2)^2 7.065 = pi (3/2)^2

50.24 = pi *4^2 7.065 = pi (9/4)

50.24 = 16 pi 7.065 ( 4/9) = pi

50.24/16 = pi pi = 3.14

pi = 3.14

Part C

We see that pi is the constant ≈ 3.14

Step-by-step explanation:

step 1. c (circumference) = (pi)d

step 2. 25.12 = (pi)(8) (part A)

step 3. pi = 3.14 (circle A)

step 4. A (area) = (pi)r^2

step 5. 50.24 = (pi)(4)^2 = 16(pi) (part B)

step 6. pi = 3.14 (circle A)

step 7. 9.42 = (pi)(3) (part A)

step 8. pi = 3.14 (circle B)

step 9. 7.065 = (pi)(1.5)^2 = 2.25(pi) (part B)

step 10. pi = 3.14 (circle B)

step 11. the values for pi are the same.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

answer: 1475

step-by-step explanation:

becuase you have to know what they are asking you