The graph of y = f(x) has the line x = 5 as an axis of symmetry. The graph also passes through the point (8,-7). Find another point that must lie on the graph of y = f(x).

You are missing an entire paragraph of information that is needed to solve what you've actually posted. Luckily for you, I answered this question once before.

Here is the ENTIRE QUESTION:

The graph of y = f(x) is a parabola whose vertex is at (1, -2). The graph of y = f(x - 3) is also a parabola. Where is the vertex of the graph of y = f(x-3)? Write your answer as an ordered pair.

Solution:

The "f( x - 3)" shifts the the graph of f(x) to the right by 3 units.

So...the vertex of f(x - 3) is ( 4, - 2).

2. The graph of y = f(x) has the line x = 5 as an axis of symmetry. The graph also passes through the point (8,-7). Find another point that must lie on the graph of y = f(x).

Here is the solution you are looking for.

If the graph has an axis of symmetry of x = 5 and (8, -7) is on the graph, we simply add 3 to 5 to get (8,-7). Afterwards, we must subtract 3 from 5 to get : (5 - 3, -7) = (2, -7) is also on the graph.

Notice that the y-coordinate is unaffected. Cool, right?

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

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