A ball is thrown straight up into the air from a height of 5 feet and at an initial speed of 20 feet/second. Let s(t) denote the vertical position of the ball (measured in feet), v(t) denote the velocity of the ball (measured in feet/second), and a(t) denote the acceleration of the ball (measured in feet/second2). From physics, we know that s′(t) = v(t) and v′(t) = a(t). The careful reader will notice you have also been given s(0) and v(0) already for this particular situation. If you are told that the ball’s acceleration is given by a(t) = −16, find an equation for the po- sition of the ball (that is, find s(t)). (Hint: you are finding a particular solution of a differential equation with two initial conditions, provided above)

what is all that apply?

24

step-by-step explanation:

the graph shows 30% of students walk. 80 students were questioned, so the number that said they walk is

30% × 80 = 0.30 × 80 = 24

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.